-9.8x^2+49x+58.8=0

Solution for -9.8x^2+49x+58.8=0 equation:

-9.8x^2+49x+58.8=0

a = -9.8; b = 49; c = +58.8;
Δ = b2-4ac
Δ = 492-4·(-9.8)·58.8
Δ = 4705.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(49)-\sqrt{4705.96}}{2*-9.8}=\frac{-49-\sqrt{4705.96}}{-19.6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(49)+\sqrt{4705.96}}{2*-9.8}=\frac{-49+\sqrt{4705.96}}{-19.6}
$